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Unix SED & awk- File processing
http://sed.sourceforge.net/sedfaq3.html
I'd like to skip first two or three fields at the the beginning of a line and print the rest of line. Consider the following input:
You can use the awk command as follows:
I'd like to skip first two or three fields at the the beginning of a line and print the rest of line. Consider the following input:
This is a testI want my input file with the following output:
Giving back more than we take
a testHow do I printing lines from the nth field using awk under UNIX or Linux operating systems?
more than we take
You can use the awk command as follows:
echo 'This is a test' | awk '{print substr($0, index($0,$3))}'OR
awk '{print substr($0, index($0,$3))}' <<< 'This is a test'You can also use the cut command:
echo 'This is a test' | cut -d ' ' -f3-OR
cut -d ' ' -f3- <<<'This is a test'Finally, process the file using bash while loop:
#!/bin/bash _input="/path/to/file.name.txt" while IFS= read -r line do cut -d ' ' -f3- <<<"$line" ### same stuff with awk ### ### awk '{print substr($0, index($0,$3))}' <<< "$line" ### done < "${_input}"Please note that you can also use Perl, Python or other shell text processing commands to do the same thing.
Unix Commands ZIP
The syntax is as follows:
zip file.zip file1.txt file2.doc photo.jpg
To zip resume.doc and all *.c file, enter:
zip bacup.zip resume.doc *.c
To zip data directory, enter:zip -r backup.zip data
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